To calculate: The vertices and foci of the conic section: x29 + y24=1

Jerold 2021-01-31 Answered
To calculate: The vertices and foci of the conic section: x29 + y24=1
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Expert Answer

Nola Robson
Answered 2021-02-01 Author has 94 answers

Step 1

Formula Used: Eccentricity (e)=1  b2a2

Step 2

Calculation: Compare the given equation with the equation of an ellipse x2a2 + y2b2=1 and we get: a2=9  a=3      b2=4  b=2

Now, e=1  b2a2=1  49=53

Vertices are: (± a, 0) and (0, ± b)

Now, put the values of a and b to get the vertice of the conic section and we get: (± a, 0) and (0, ± b)=(± 3, 0) and (0, ± 2) Now, Foci =(± ae, 0)=(± 5, 0)

Thus, the vertices and foci of the conic section are: (± 3, 0) and (0, ± 2) and (± 5, 0).

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