Question

Two independent measurements are made of the lifetime of a charmed strange meson. Each measurement has a standard deviation of 7times 10^{−15} seconds. The lifetime of the meson is estimated by averaging the two measurements. What is the standard deviation of this estimate ?

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asked 2021-02-12
Two independent measurements are made of the lifetime of a charmed strange meson. Each measurement has a standard deviation of \(7\times 10^{−15}\) seconds. The lifetime of the meson is estimated by averaging the two measurements.
What is the standard deviation of this estimate ?

Answers (1)

2021-02-13
Step 1
It is given that the population standard deviation is \(7\times 10^{−15}\).
The lifetime of the meson is estimated by averaging the two measurements.
The standard deviation of the two measurements is obtained by dividing the population standard deviation by square \(\sqrt[2]{}\).
Step 2
Thus, the standard deviation of the estimate is, \(SD=\frac{7\times 10^{-15}}{\sqrt{2}}=4.9497\times10^{-15}\).
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