Factoring Quadratic Formula Equation \(\displaystyle{2}{x}{y}^{{{2}}}+{8}{x}{y}-{z}={0}\) \(\displaystyle{y}={\frac{{-{8}{x}\pm\sqrt{{{\left({8}{x}\right)}^{{2}}-{4}{\left({2}{x}\right)}{\left(-{z}\right)}}}}}{{{2}{\left({2}{x}\right)}}}}\)

Adolfo Hebert

Adolfo Hebert

Answered question

2022-04-02

Factoring Quadratic Formula Equation
2xy2+8xyz=0
y=8x±(8x)24(2x)(z)2(2x)

Answer & Explanation

Malia Booth

Malia Booth

Beginner2022-04-03Added 16 answers

The numerator and denominator have been divided by 4x, which becomes 16x2 inside the square root. Since 4x is the denominator, it disappears and we are left with
y=8x4x±64x216x2+8xz16x2=z2x+42
Clearly this only works if x0.

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