To check: Whether the set of numbers {sqrt{3}, pi, frac{sqrt[3]{2}}{4}, sqrt{5}} contains integers, rational numbers, and (or) irrational numbers.

To check: Whether the set of numbers {sqrt{3}, pi, frac{sqrt[3]{2}}{4}, sqrt{5}} contains integers, rational numbers, and (or) irrational numbers.

Question
Decimals
asked 2020-10-18
To check: Whether the set of numbers \(\displaystyle{\left\lbrace\sqrt{{{3}}},\pi,{\frac{{\sqrt{{{3}}}{\left\lbrace{2}\right\rbrace}}}{{{4}}}},\sqrt{{{5}}}\right\rbrace}\) contains integers, rational numbers, and (or) irrational numbers.

Answers (1)

2020-10-19

Result used: Rational number: Rational numbers are numbers that can be written in the form \(\displaystyle{\frac{{{p}}}{{{q}}}}\), where p and q are integers with \(\displaystyle{q}\ne{q}{0}\). The rational numbers can be written as terminating or repeating decimals. Irrational number: The irrational numbers are set of all real numbers that not rational numbers. The irrationals cannot be written as terminating or repeating decimals. Verification: The given set of numbers is \(\displaystyle{\left\lbrace\sqrt{{{3}}},\pi,{\frac{{\sqrt{{{3}}}{\left\lbrace{2}\right\rbrace}}}{{{4}}}},\sqrt{{{5}}}\right\rbrace}\) Observe that the elements \(\sqrt{3}=1.732\cdots,\pi=3.14\cdots,\frac{\sqrt{3}\{2\}}{4}=0.315\cdots,\text{and}\sqrt{5}=2.236\cdots\) are non-terminating decimals. Therefore, by the definition of the irrational numbers, all the numbers in the given set are irrational. Answer: Thus, the set numbers \(\displaystyle{\left\lbrace\sqrt{{{3}}},\pi,{\frac{{\sqrt{{{3}}}{\left\lbrace{2}\right\rbrace}}}{{{4}}}},\sqrt{{{5}}}\right\rbrace}\) contains irrational numbers.

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