Evaluating \(\displaystyle{\sin{{\left({\arccos{{\frac{{{1}}}{{{2}}}}}}+{\arccos{{\frac{{{7}}}{{{25}}}}}}\right)}}}\)

rhedynogh0rp

rhedynogh0rp

Answered question

2022-04-05

Evaluating sin(arccos12+arccos725)

Answer & Explanation

Jayda Burch

Jayda Burch

Beginner2022-04-06Added 10 answers

sin(arccos12+arccos725)=
sin(x+y)=sinxcosy+cosxsiny
Where
x=arccos12
and
y=arccos725
Note that
cosx=12
and
cosy=725
We can find
sinx=32
and
siny=2425
upon substitution we get
sin(arccos12+arccos725)=
7350+2450=73+2450

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