\(\displaystyle{e}^{{{3}}}={20.0855}\)
Taking log on both side
\(\displaystyle{{\log{{e}}}^{{{3}}}=}{\log{\ }}{20.0855}\)
We know log property
\(\displaystyle{{\log{{m}}}^{{{n}}}=}{n}\ {\log{\ }}{m}\)
Therefore
Answer:
\(\displaystyle{3}\ {\log{\ }}{e}={\log{\ }}{20.0855}\)