The front 1.20 m of a 1 400-kg

Answered question

2022-04-07

The front 1.20 m of a 1 400-kg car is designed as a “crum- ple zone” that collapses to absorb the shock of a collision. If a car traveling 25.0 m/s stops uniformly in 1.20 m, (a) how long does the collision last, (b) what is the mag- nitude of the average force on the car, and (c) what is the acceleration of the car? Express the acceleration as a mul- tiple of the acceleration of gravity.

Answer & Explanation

nick1337

nick1337

Expert2022-04-19Added 777 answers

a) vf2+vi2=2ad

02-252=2(a)(1.20)

-260.42 m/s2

vf=vi+at

t=0-25-260.42

t=0.096 s

b) favg=m×a =1400×260.42

favg=364600 N

c) a=260.429.8

a=26.5 g

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