State domain, range, vertical asymptote and \(\displaystyle{x},{y}\)

sexoagotadorogyr

sexoagotadorogyr

Answered question

2022-04-03

State domain, range, vertical asymptote and x,y intercepts for log4(x1)+1

Answer & Explanation

Janessa Foster

Janessa Foster

Beginner2022-04-04Added 12 answers

Looks all fine. You can solve the equation straightforward.
log4(x1)+1=0
log4(x1)=1
Writing both sides into the exponent with base 4.
4log4(x1)=41
x1=14

Ireland Vaughan

Ireland Vaughan

Beginner2022-04-05Added 14 answers

Let x-intercept (intersection of curve with x-axis) of
y(x)=log4(x1)+1 be (a,0), This means to find a one has to solve
1+log4(a1)=0
(a1)=41
This is false. y-intercept is a point (0,b) on the curve. For example, y(x)=log4(x+1) has y-intercept at (0,0).
One has to check if x=0 is in the domain of y(x)=log4(x1)+1. Now argue that it is not. Domain is x>1.

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