\(\displaystyle{H}{\left({s}\right)}={\frac{{{s}-{5}}}{{{\left({s}-{3}\right)}{\left({s}-{1}\right)}}}}\) The inverse Laplace transform of H(s)

jisu61hbke 2022-03-31 Answered
The inverse Laplace transform of H(s) is equal to
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Answered 2022-04-01 Author has 14 answers
Note that we can write
Then, f(t)=δ(t)2e3tu(t) and
Note that partial fraction expansion makes things easier. We simply write
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