Solve my Other example. Here is a photo

Answered question

2022-04-06

nick1337

Expert2022-04-19Added 777 answers

1) Heat required = mass $\times$ latent heat

$Q = 0.15 \times 871 \times 10^{3}$

$Q = 1.31 \times 10^{5} J$

2) heat removed to change temperature:

$Q = m \times C \times d T$

$m =$ mass

$C =$ heat capacity

$d T =$ change in temp $= (18 - 0) = 18 K$

$Q = 0.35 \times 4.19 \times 103 \times 18$

$Q = 26.4 \times 1000 J$

$Q = (26.4 / 4.2) \times kcal$

$Q = 6.3 kcal .$

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