I am interested in the following differential equation:

Jazmyn Holden

Jazmyn Holden

Answered question

2022-04-01

I am interested in the following differential equation: yqy where q:R+R+ is a continuous, positive function.

Answer & Explanation

memantangti17

memantangti17

Beginner2022-04-02Added 13 answers

Step 1
y=py
yy=pyy
y2=py2py2dx by integration by parts.
For a vanishingly small region about a zero of y, that integral is zero. This implies a zero of y happens for a zero of the first derivative.
The second derivative is always non-negative, so the first derivative is monotonically increasing. Once positive, the first derivative will remain positive, so it only has a zero if it has a negative initial value.
The first derivative will exceed any initial value, so any a<0 will work.
So k=0

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