How to solve \(\displaystyle\text{f{x}''(t)=\begin{bmatrix}-1&0\\0&-1\end{bmatrix}\textbf{x}(t}{f}{\left\lbrace{x}\right\rbrace}{''}{\left({t}\right)}={b}{e}{g}\in{\left\lbrace{b}{m}{a}{t}{r}{i}{x}\right\rbrace}-{1}&{0}\backslash{0}&-{1}{e}{n}{d}{\left\lbrace{b}{m}{a}{t}{r}{i}{x}\right\rbrace}\text{f{x}(t}{f}{\left\lbrace{x}\right\rbrace}{\left({t}\right)}\) What I'm thinking is

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