How to solve \(\displaystyle{5}-{{\log}_{{2}}{\left({x}-{3}\right)}}={{\log}_{{2}}{\left({x}+{1}\right)}}\)

encaderpwp

encaderpwp

Answered question

2022-04-01

How to solve
5log2(x3)=log2(x+1)

Answer & Explanation

smekkleg5hhp

smekkleg5hhp

Beginner2022-04-02Added 8 answers

Put all log terms on one side:
5=log2(x3)+log2(x+1).
Then, write the log terms using only one logarithm (use the law log2a+log2b=log2(ab)
5=log2((x3)(x+1)).
To get rid of the log, recall, logax=yay=x, so the above equation can be written as
25=(x3)(x+1).
Can you take it from here?

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