\(\displaystyle\alpha\) is a root of the equation

Alfredo Holmes 2022-03-28 Answered
α is a root of the equation px2+2qx+r=0 or not where the following determinant is given 0
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Answers (1)

Luciana Cline
Answered 2022-03-29 Author has 14 answers

Step 1
Your determinant value seems to be wrong. The correct determinant is
-α2p2r+α2pq2-2αpqr+2αq3-pr2+q2r
=-(pr-q2)(α2p+2qα+r)
so unless pr=q2, α is indeed a root of px2+2qx+r

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