Proving \(\displaystyle{1}+{{\tan}^{{2}}{\left({x}\right)}}={{\sec}^{{2}}{\left({x}\right)}}\)

Harold Hoover

Harold Hoover

Answered question

2022-03-30

Proving 1+tan2(x)=sec2(x)

Answer & Explanation

Yaritza Phillips

Yaritza Phillips

Beginner2022-03-31Added 12 answers

Note simply that
1+tan2(x)=1+sin2xcos2x=
=cos2x+sin2xcos2x=
=1cos2x=sec2(x)

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