Prove the identity \(\displaystyle{\cos{{\frac{{{x}}}{{{2}}}}}}\cdot{\cos{{\frac{{{x}}}{{{4}}}}}}\cdot{\cos{{\frac{{{x}}}{{{8}}}}}}={\frac{{{\sin{{x}}}}}{{{8}{\sin{{\frac{{{x}}}{{{8}}}}}}}}}\)

Ashleigh Shaffer

Ashleigh Shaffer

Answered question

2022-03-30

Prove the identity
cosx2cosx4cosx8=sinx8sinx8

Answer & Explanation

Malia Booth

Malia Booth

Beginner2022-03-31Added 16 answers

We have
cosx2cosx4cosx8×8sinx8=4cosx2cosx4sinx4
=2cosx2sinx2=sinx
The generalization is
k=1ncosx2k=sinx2nsinx2n

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