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Step 1 Given: p(x)=x2+5x+6 Step 2 To find the zeroes p(x)=0 x2+5x+6=0 x(x+3)+2(x+3)=0 (x+3)(x+2)=0 x=−3, x=−2 The zeroes of p(x) are -3 and -2
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