Determining convergence of a series \(\displaystyle{\sum_{{{n}={0}}}^{\infty}}\sqrt{{{n}}}{\left(\sqrt{{{n}^{{4}}+{1}}}-{n}^{{2}}\right)}\)

xxgetthisar08

xxgetthisar08

Answered question

2022-03-28

Determining convergence of a series
n=0n(n4+1n2)

Answer & Explanation

Jesse Gates

Jesse Gates

Beginner2022-03-29Added 19 answers

Just note that
n4+1n2=(n4+1n2)(n4+1+n2)n4+1+n2
=n4+1n4n4+1+n2
=1n4+1+n2
then you can use the comparison test.

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