Definition of polynomial ring Given a ring R, the

anadyrskia0g5

anadyrskia0g5

Answered question

2022-03-27

Definition of polynomial ring
Given a ring R, the polynomial ring is defined as
R[x] ={k=0nakxk:n0, akR for  k{0,1,,n}}.
However, it is not usually specified what x is. In order for multiplication to make sense, I guess it has to be an element in R at least. But is R[x] the set of all functions P:RR,given by  xk=0nakxk, or the set of those functions evaluated at x?
Sometimes R is required to be commutative. Does that make any difference for R[x]?

Answer & Explanation

zalutaloj9a0f

zalutaloj9a0f

Beginner2022-03-28Added 17 answers

We think of polynomials as infinite lists which have a finite point in after which everything is 0. (Meaning that a polynomial is of finite degree by definition.)
For example the polynomial x2+1 is actually the infinite list (1,0,1,0,0,). (Think of the first element as the 0-th element, then n-th element in the list corresponds to the coefficient of xn, notice that the list can contain numbers or more generally, elements of any ring.)
The operations are defined on this concept but this writing is not practical so we switch to the notation with x.
Usually the books just say x to be an indeterminate.
Cecilia Nolan

Cecilia Nolan

Beginner2022-03-29Added 13 answers

Explanation:
First, x is an unknown over R. This means that x does not satisfy any nontrivial equation over R:k=0nakxk=0 with not all ak vanishing.
Second, consider the set of all functions P:xk=0nakxk. If R is an infinite field of char 0, two different polynomials define different polynomial functions, but this property is false for finite fields.
Third, if R is commutative, then R[x] is commutative.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?