Definite Integral \(\displaystyle{\int_{{{\frac{{\pi}}{{{12}}}}}}^{{{\frac{{\pi}}{{{4}}}}}}}{\frac{{{8}{\cos{{2}}}{x}}}{{{\left({\tan{{x}}}+{\cot{{x}}}\right)}^{{3}}}}}{\left.{d}{x}\right.}\)

svezic0rn

svezic0rn

Answered question

2022-03-25

Definite Integral π12π48cos2x(tanx+cotx)3dx

Answer & Explanation

yaum3xg1

yaum3xg1

Beginner2022-03-26Added 12 answers

tanx+cotx=2sin2x so
I=π12π48cos2xsin32x,dx=18sin42xπ12π4=15128

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