Definite integral \(\displaystyle{\int_{{1}}^{{\frac{\pi}{{8}}}}}{\left({x}-{1}\right)}{\sin{{4}}}{x}{\left.{d}{x}\right.}\)

ashes86047xhz

ashes86047xhz

Answered question

2022-03-25

Definite integral
1π8(x1)sin4xdx

Answer & Explanation

horieblersee275

horieblersee275

Beginner2022-03-26Added 17 answers

To begin, let us find the antiderivative by integration by parts. If we allow u=x1 and dv=sin(4x)dx, it follows that du=dx and v=14cos(4x).
We continue as follows:
(x1)sin(4x)dx
=14(x1)cos(4x)14cos(4x)dx
=14(x1)cos(4x)+116sin(4x)+C
Now we evaluate the definite integral by finding the difference in the values of the antiderivative at x=π8 and x=1 The answer is approximately 0.110

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