Given:

A group consists of 6 men and 6 women. Divide into groups 6 in each.

pancha3
2021-01-30
Answered

To find: The probability of getting same number of men in two groups.

Given:

A group consists of 6 men and 6 women. Divide into groups 6 in each.

Given:

A group consists of 6 men and 6 women. Divide into groups 6 in each.

You can still ask an expert for help

grbavit

Answered 2021-01-31
Author has **109** answers

Calculation:

Total number of people$=6+6=12$

All possible ways of dividing 12 people in to two groups with 6 people in each

$=\frac{12!}{6!6!}$

$=924$

If both groups are having same number of menm then each group consist 3 men and 3 women.

The possible ways of getting 3 men and 3 women in each group is

$=\frac{6!}{3!3!}\times \frac{6!}{3!3!}$

$=20\times 20$

$=400$

P(same number of men in each group)$=\frac{400}{924}$

$=0.4329$

Hence, the probability$=0.4329$

Answer:

The probability of getting equal number of men in two groups$=0.4329$

Total number of people

All possible ways of dividing 12 people in to two groups with 6 people in each

If both groups are having same number of menm then each group consist 3 men and 3 women.

The possible ways of getting 3 men and 3 women in each group is

P(same number of men in each group)

Hence, the probability

Answer:

The probability of getting equal number of men in two groups

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