Compute \(\displaystyle\int{\frac{{{x}^{{2}}}}{{{\tan{{\left\lbrace{x}\right\rbrace}}}-{x}}}}{\left.{d}{x}\right.}\) for \(\displaystyle{x}\in{\left({0},{\frac{{\pi}}{{{2}}}}\right)}\)

Samara Richard

Samara Richard

Answered question

2022-03-27

Compute x2tan{x}xdx for x(0,π2)

Answer & Explanation

Luciana Cline

Luciana Cline

Beginner2022-03-28Added 14 answers

x2tan{x}xdx=(x2tan{x}x+xx)dx=xsin{x}sin{x}xcos{x}dxx22=
=d(sinxxcosx)sinxxcosxx22=ln|sinxxcosx|x22+C
Ashton Conrad

Ashton Conrad

Beginner2022-03-29Added 11 answers

x2tan{x}x=x2cosx+xsinxxsinxsin{x}xcosx=(xsinxsin{x}xcosxx)
Now notice that
sinxxcosx=txsinx=dt
Hence
(xsinxsinxxcosxx)=ln|(sinxxcosx)|x22+C

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