How come \(\displaystyle\lim_{{{x}\to\infty}}{x}-{\ln{{\left({1}+{e}^{{x}}\right)}}}={0}\) ?

parksinta8rkv

parksinta8rkv

Answered question

2022-03-25

How come
limxxln(1+ex)=0 ?

Answer & Explanation

uqhekekocj8f

uqhekekocj8f

Beginner2022-03-26Added 8 answers

formally
xlog(1+ex)=log(ex)log(1+ex)=log(ex1+ex)=log(1+ex)0
but you can think about log(1+ex) being almost equal to log(ex)=x for intuition.

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