Find the derivative of the following functions \(\displaystyle{y}={\left({x}^{{{2}}}+{1}\right)}{\ln{{x}}}\)

Javion Kerr

Javion Kerr

Answered question

2022-03-22

Find the derivative of the following functions
y=(x2+1)lnx

Answer & Explanation

Esteban Sloan

Esteban Sloan

Beginner2022-03-23Added 21 answers

Step 1
Given: y=(x2+1)lnx
we know that
ddx(uv)=vdudx+udvdx...(1)
Step 2
so, by using equation(1)
dydx=ddx[(x2+1)lnx]
=(lnx)ddx(x2+1)+(x2+1)ddx(lnx)
(ddx(xn)=nxn1,ddx(lnx)=1x)
=(lnx)(2x+0)+(x2+1)1x
=2xlnx+x2+1x
hence, derivative of given function is 2xlnx+x2+1x.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?