sendetimejhn

sendetimejhn

Answered question

2022-03-25

Given that lim_(x->2)f(x)=7,g is continuous at 3, and lim_(x->3)g(x)=3, find the limit lim_(x->2)(xf(x)-x^3)/(g(x+1))

Answer & Explanation

RizerMix

RizerMix

Expert2022-05-03Added 656 answers


limx2xf(x)-x3g(x+1)

Split the limit using the Limits Quotient Rule on the limit as x approaches 2.

limx2xf(x)-x3limx2g(x+1)

Split the limit using the Sum of Limits Rule on the limit as xx approaches 2.

limx2xf(x)-limx2x3limx2g(x+1)

Split the limit using the Product of Limits Rule on the limit as x approaches 2.

limx2xlimx2f(x)-limx2x3limx2g(x+1)

Move the exponent 3 from x3 outside the limit using the Limits Power Rule.

limx2xlimx2f(x)-(limx2x)3limx2g(x+1)

Evaluate the limits by plugging in 2 for all occurrences of x.

Evaluate the limit of x by plugging in 2 for x.

2limx2f(x)-(limx2x)3limx2g(x+1)

Evaluate the limit of f(x) by plugging in 2 for x.

2f(2)-(limx2x)3limx2g(x+1)

Evaluate the limit of x by plugging in 2 for x.

2f(2)-23limx2g(x+1)

Evaluate the limit of g(x+1) by plugging in 2 for x.

2f(2)-23g(2+1)

Add 2 and 1.

2f(2)-23g(3)

Simplify the numerator.

Raise 2 to the power of 3.

2f(2)-18g(3)

Multiply -1 by 8.

 

2f(2)8g(3)
 

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