Any tricky method to solve this one? The question

Kayden Chandler

Kayden Chandler

Answered question

2022-03-16

Any tricky method to solve this one?
The question : Prove that :
  if  y=2x21,  then  [1y+13y3+15y5+]
is equal to
12[1x2+12x4+13x6+]
Here I have modified the question, in the actual question (from my paper) there were four other options given,my approach was to reduce the first expression to 12ln(y+1y1) and then trying to check for each options to find the match, now is there any other approach for this one ? Since it took me sometime for checking each options :( and the desired answer is at the last option!

Answer & Explanation

brelhadorqkh

brelhadorqkh

Beginner2022-03-17Added 3 answers

One you simplify to 12log(y+1y1) , plug in y=2x21 and simplify it to get 12log(11x2). Now expand to get the desired answer.

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