What is the slope of \(\displaystyle{f{{\left({x}\right)}}}=-{x}{\frac{{{e}^{{{x}}}}}{{{x}^{{{2}}}}}}\) at

Israel Franklin

Israel Franklin

Answered question

2022-03-14

What is the slope of f(x)=xexx2 at x=1?

Answer & Explanation

Ettrapinithr

Ettrapinithr

Beginner2022-03-15Added 7 answers

f(x)=xexx2=exx=exx1
f(x)=(ex(x2)+x1ex) (Product, Exponential and Power Rules)
The slope of f(x) at x=1 is given by f'(1)
f(1)=(e1(1)+e11)
f'(1)=-(-e+e)=0
Hence: Slope of f(x) at x=1 is 0

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