why \log(n!) isn't zero? I have wondered that why the \log

Neatlyvat91g

Neatlyvat91g

Answered question

2022-03-09

why log(n!) isn't zero?
I have wondered that why the log(n!) isn't zero for nN
Because I think that log(1) is zero so all following numbers after multiplying the result will become zero.
Thanks in advance.

Answer & Explanation

Alexa Lewis

Alexa Lewis

Beginner2022-03-10Added 1 answers

Might as well make an answer of it.
log(n!)=log(123n)
=log1+log2+log3++logn
=log2+log3++logn
so it won’t be 0 unless n=1 (or n=0): you’re adding the logs, not multiplying them
InnovaRat0r5

InnovaRat0r5

Beginner2022-03-11Added 1 answers

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