Solve differential equation \frac{dy}{dx}= (x+y+1)^2-(x+y-1)^2

Solve differential equation $\frac{dy}{dx}={\left(x+y+1\right)}^{2}-{\left(x+y-1\right)}^{2}$
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On substituting
$\frac{dy}{dx}={y}^{t}$
${y}^{t}={\left(x+y+1\right)}^{2}-{\left(x+y-1\right)}^{2}$
${y}^{t}-4y=4x$
On finding the integration factor
$\mu \left(x\right)={e}^{-4}x$
Thus on writing the equation in the form
${\left(\mu \left(x\right)y\right)}^{\prime }=\mu \left(x\right)q\left(x\right)$
${\left({e}^{-4}y\right)}^{\prime }=4x{e}^{-4}$
$y=-x-\frac{1}{4}+{c}_{1}{e}^{4x}$
Jeffrey Jordon