# The product of matrix B and C is matrix D begin{bmatrix}2 & -1&4 g & 0&32&h&0 end{bmatrix} times begin{bmatrix}-1 & 5 4&f-3&1 end{bmatrix}=begin{bmatr

The product of matrix B and C is matrix D
$\left[\begin{array}{ccc}2& -1& 4\\ g& 0& 3\\ 2& h& 0\end{array}\right]×\left[\begin{array}{cc}-1& 5\\ 4& f\\ -3& 1\end{array}\right]=\left[\begin{array}{cc}i& 24\\ -16& -4\\ 4& e\end{array}\right]$
3.From the expression above, what should be the value of e?
4.From the expression above, what should be the value of g?
5.From the expression above, what should be the value of f?
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rogreenhoxa8
Step 1 We are given the two matrices namely
Using the basic rules of multiplication, we have
$B×C=2\left[\begin{array}{ccc}2& -1& 4\\ g& 0& 3\\ 2& h& 0\end{array}\right]×\left[\begin{array}{cc}-1& 5\\ 4& f\\ -3& 1\end{array}\right]$
$⇒B×C=\left[\begin{array}{ccc}4& -2& 8\\ 2g& 0& 6\\ 4& 4h& 0\end{array}\right]×\left[\begin{array}{cc}-1& 5\\ 4& f\\ -3& 1\end{array}\right]$
$⇒B×C=\left[\begin{array}{cc}-4-8-24& 20-2f+8\\ -2g+0-18& 10g+6\\ -4+8h+0& 20+2hf+0\end{array}\right]$
Step 2
Now, we have $B×C=\left[\begin{array}{cc}-4-8-24& 20-2f+8\\ -2g+0-18& 10g+6\\ -4+8h+0& 20+2hf+0\end{array}\right]$ . We are also given that $B×C=\left[\begin{array}{cc}i& 24\\ -16& -4\\ 4& e\end{array}\right]$
Therefore, we now have
$B×C=\left[\begin{array}{cc}-4-8-24& 20-2f+8\\ -2g+0-18& 10g+6\\ -4+8h+0& 20+2hf+0\end{array}\right]=\left[\begin{array}{cc}i& 24\\ -16& -4\\ 4& e\end{array}\right]$. Comparing the entries of the matrices, we have
-36=i, 28-2f=24
2g+18=16,10g+6=-4
8h-4=4,20+2hf=e
Solving these equations, we get
i=-36,f=2,g=-1,h=1,e=24
Step 3
(3). Answer: The value of e is 24.
(4). Answer: The value of g is -1.
(5). Answer: The value of f is 2.
Jeffrey Jordon