4-th derivative of \frac{(1+x+x^2)}{(1-x+x^2)} usibg Taylor polynomial for \frac{1}{1-x}

cooopt392a0i

cooopt392a0i

Answered question

2022-03-03

4-th derivative of (1+x+x2)(1x+x2) usibg Taylor polynomial for 11x

Answer & Explanation

Katey Guzman

Katey Guzman

Beginner2022-03-04Added 4 answers

f2(x)=1+x+x21x+x2
=(1+x+x2)(1+x)(1x+x2)(1+x)
=(1+x+x2)(1+x)1+x3
=1+2x+2x2+x31+x3
=1+21+x1+x3
=1+211+x3+2x11+x3

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?