Evaluate the integrals. \int \frac{\sin^{-1}x}{\sqrt{1-x^{2}}}dx

Aneeka Hunt 2021-02-12 Answered
Evaluate the integrals.
sin1x1x2dx
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Expert Answer

BleabyinfibiaG
Answered 2021-02-13 Author has 118 answers
Step 1
Consider the provided integral,
sin1x1x2dx
Evaluate the integrals.
Apply the Substitution method,
u=sin1xdu=11x2dx
Step 2
Therefore,
sin1x1x2dx=udu
=u1+11+1+C
=u22+C
Substitute back u=sin1x.
sin1x1x2dx=(sin1x)22+C
=12(sin1x)2+C
Hence.
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