Evaluate the integrals. \int_{-2}^{2}(3x^{4}-2x+1)dx

Clifland

Clifland

Answered question

2021-01-28

Evaluate the integrals.
22(3x42x+1)dx

Answer & Explanation

yagombyeR

yagombyeR

Skilled2021-01-29Added 92 answers

Step 1: Given that
Evaluate integrals.
22(3x42x+1)dx
Step 2: Solving the integral
We have,
K22(3x42x+1)dx=223x4dx222xdx+221dx=3[x55]222[x22]22+[x]22
=35[25(2)5][22(2)2]+[2(2)]
=35(32(32))(44)+(2+2)
=35(64)0+4
=1925+4
=192+205
=2125
=42.4

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?