Evaluate the integrals. \int_{-2}^{2}(3x^{4}-2x+1)dx

Clifland 2021-01-28 Answered
Evaluate the integrals.
22(3x42x+1)dx
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Expert Answer

yagombyeR
Answered 2021-01-29 Author has 92 answers

Step 1: Given that
Evaluate integrals.
22(3x42x+1)dx
Step 2: Solving the integral
We have,
K22(3x42x+1)dx=223x4dx222xdx+221dx=3[x55]222[x22]22+[x]22
=35[25(2)5][22(2)2]+[2(2)]
=35(32(32))(44)+(2+2)
=35(64)0+4
=1925+4
=192+205
=2125
=42.4

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