Evaluate the following definite integrals \int_{0}^{1}(x^{4}+7e^{x}-3)dx

snowlovelydayM 2020-12-17 Answered
Evaluate the following definite integrals
01(x4+7ex3)dx
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Expert Answer

cyhuddwyr9
Answered 2020-12-18 Author has 90 answers

Given that
01(x4+7ex3)dx
=[x55+7ex3x]01 [xndx=xn+1n+1+Cexdx=ex+C]
=15+7e13(1)07e0+3(0)
=15+7e10
=7e495
01(x4+7ex3)dx=7e495

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