Evaluate the following definite integrals \int_{0}^{1}xe^{(-x^{2}+2)}dx

SchachtN 2021-02-18 Answered
Evaluate the following definite integrals
01xe(x2+2)dx
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Expert Answer

i1ziZ
Answered 2021-02-19 Author has 92 answers
Step 1
To Evaluate the following definite integrals:
Step 2
Given that
01xe(x2+2)dx
Let e(x2+2)=u
dudx=2x(ex2+2)
du2=xe(x2+2)dx
Hence 01xe(x2+2)dx=01du2
12[4]01
=12[e1e2]
=12[ee2]=12[e2e]
01xe(x2+2)dx=12(e2e)
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Jeffrey Jordon
Answered 2021-11-05 Author has 2087 answers

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