I want to find out value of this expression \cos^2 48^\circ-\sin^2

Nettie Potts

Nettie Potts

Answered question

2022-03-01

I want to find out value of this expression
cos248sin212

Answer & Explanation

Kathleen Mcpherson

Kathleen Mcpherson

Beginner2022-03-02Added 9 answers

cos2(48)sin2(12)=sin2(42)sin2(12)=sin(54)sin(30)
=12(51)
Here we used the formula-
sin2(A)sin2(B)=sin(A+B)sin(AB)
and sin(54)=151
an2gi2m9gg

an2gi2m9gg

Beginner2022-03-03Added 9 answers

I've got a formula :
cos(A+B)cos(AB)=cos2Asin2B
so from this formula this question is now easy
=cos248sin212
=cos60cos36
=5+18

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