I'm trying to solve a differential equation which is : y'(t)-4y(t)=\cos(3t)

sacateundisco8i3

sacateundisco8i3

Answered question

2022-03-01

I'm trying to solve a differential equation which is :
y(t)4y(t)=cos(3t)

Answer & Explanation

aksemaktjya

aksemaktjya

Beginner2022-03-02Added 6 answers

Use operator D=ddx
y4y=cos(3t)(D4)y=cos(3t)
y(t)=1D40+1D4cos(3t)
y(t)=Ce4t+D+4D216cos(3t)=Ce4t+Dcos(3t)+4cos(3t)3216
y(t)=Ce4t125[4cos(3t)3sin(3t)]
Therefore, the period of the particular solution is T=2π3

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