Evaluate the integral using the indicated substitution. \int2x(x^{2}+1)^{23}dx,\ u=x^{2}+1

Carol Gates 2021-02-12 Answered
Evaluate the integral using the indicated substitution.
2x(x2+1)23dx, u=x2+1
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Expert Answer

Sally Cresswell
Answered 2021-02-13 Author has 91 answers
Step 1
Consider the integrals,
2x(x2+1)23dx...(1)
Let, u=x2+1
du=2xdx
Step 2
Substitute all value in equation (1) then,
2x(x2+1)23dx=u23du
=u2424+C
Substitute back, u=x2+1
2x(x2+1)23dx=124(x2+1)24+C
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Jeffrey Jordon
Answered 2021-11-05 Author has 2070 answers

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