Solve the following integral \int_{0}^{4}3x(4-x)dx=32 \int_{0}^{4}x(x-4)dx

Phoebe 2020-11-12 Answered
Solve the following integral
043x(4x)dx=32
04x(x4)dx
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Expert Answer

wheezym
Answered 2020-11-13 Author has 103 answers
Step 1
043x(4x)dx=32
We have to evaluate.
04x(x4)dx
Step 2
We have, 043x(4x)dx=32...(1)
and 04x(x4)dx=?
Now,
043x(4x)dx=32
304x(4x)dx=32
04x(4x)dx=323
04x(1)(x4)dx=323
04x(x4)dx=323
04x(x4)dx=323
Hence, 04x(x4)dx=323
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Jeffrey Jordon
Answered 2021-11-05 Author has 2047 answers

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