Solve the following integral \int_{0}^{4}3x(4-x)dx=32 \int_{0}^{4}x(x-4)dx

Phoebe

Phoebe

Answered question

2020-11-12

Solve the following integral
043x(4x)dx=32
04x(x4)dx

Answer & Explanation

wheezym

wheezym

Skilled2020-11-13Added 103 answers

Step 1
043x(4x)dx=32
We have to evaluate.
04x(x4)dx
Step 2
We have, 043x(4x)dx=32...(1)
and 04x(x4)dx=?
Now,
043x(4x)dx=32
304x(4x)dx=32
04x(4x)dx=323
04x(1)(x4)dx=323
04x(x4)dx=323
04x(x4)dx=323
Hence, 04x(x4)dx=323
Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-05Added 2605 answers

Answer is given below (on video)

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