How to solve the following equation? \tan x=\tan(x+10^\circ)\tan(x+20^\circ)\tan(x+30^\circ)

Madihah Woodard

Madihah Woodard

Answered question

2022-02-28

How to solve the following equation?
tanx=tan(x+10)tan(x+20)tan(x+30)

Answer & Explanation

Miles Martin

Miles Martin

Beginner2022-03-01Added 6 answers

sinxcos(x+10)cosxsin(x+10)=sin(x+20)sin(x+30)cos(x+20)cos(x+30)
Applying componendo and dividendo,
cosxsin(x+10)+sinxcos(x+10)cosxsin(x+10)sinxcos(x+10)
=cos(x+20)cos(x+30)+sin(x+20)cos(x+30)cos(x+20)cos(x+30)sin(x+20)cos(x+30)
sin(2x+10)sin10=cos10cos(2x+50)
applying sin(A±B) and cos(A±B)
So,
sin(2x+10)cos(2x+50)=sin10cos10
sin(4x+60)sin40=sin20
(applying 2sinAcosA=sin2A and 2sinAcosB=sin(A+B)+sin(AB))
sin(4x+60)=sin40+sin20=2sin20+402cos40202
(applying sin2C+sin2D=2sin(C+D)cos(CD) and sin(90±A)=cosA)
Now

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