# Sketch the graph of the inequality. (x&nbsp;+&nbsp;2)2&nbsp;+&nbsp;y2&nbsp;&gt;&nbsp;1

Sketch the graph of the inequality.(x + 2)2 + y2 > 1
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$\left(x+2{\right)}^{2}+{y}^{2}>1$

Subtract ${\left(x+2\right)}^{2}$ from both sides of the inequality.

${y}^{2}>1-{\left(x+2\right)}^{2}$

Take the square root of both sides of the inequality to eliminate the exponent on the left side.

$\sqrt{{y}^{2}}>\sqrt{1-{\left(x+2\right)}^{2}}$

Simplify the equation.

$|y|>\sqrt{\left(x+3\right)\left(-x-1\right)}$

Write $|y|>\sqrt{\left(x+3\right)\left(-x-1\right)}$ as a piecewise.

Solve $-y>\sqrt{\left(x+3\right)\left(-x-1\right)}$ when $-3\le y\le -1$.

−3≤y≤No(Minimum)$-3\le y\le No\left(Minimum\right)$

Find the union of the solutions.

$-3\le y\le iNo\mathrm{Min}{m}^{2}u$