Question

Find the x-and y-intercepts of this equation.
\(\displaystyle{k}{\left({x}\right)}=-{5}{x}+{1}\)

Answer 1

Calculation:
Consider the following function
\(\displaystyle{k}{\left({x}\right)}=-{5}{x}+{1}\)
For x-intercept put \(\displaystyle{k}{\left({x}\right)}={0}\)
\(\displaystyle{0}=-{5}{x}+{1}\)
\(\displaystyle{5}{x}={1}\)
\(\displaystyle{x}={\frac{{{1}}}{{{5}}}}\)
Hence, the x-intercept is at \(\displaystyle{\left({\frac{{{1}}}{{{5}}}},{0}\right)}\)
For y-intercept put \(\displaystyle{x}={0}\)
\(\displaystyle{k}{\left({0}\right)}=—{5}{\left({0}\right)}+{1}={1}\)
Hence, the y-intercept is at (0, 1)