# Find the x-and y-intercepts of this equation. k(x)=-5x+1

Find the x-and y-intercepts of this equation.
$k\left(x\right)=-5x+1$
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Calculation:
Consider the following function
$k\left(x\right)=-5x+1$
For x-intercept put $k\left(x\right)=0$
$0=-5x+1$
$5x=1$
$x=\frac{1}{5}$
Hence, the x-intercept is at $\left(\frac{1}{5},0\right)$
For y-intercept put $x=0$
$k\left(0\right)=—5\left(0\right)+1=1$
Hence, the y-intercept is at (0, 1)