Find the x-and y-intercepts of this equation. 7x+2y=56

Question
Upper level algebra
asked 2020-12-17
Find the x-and y-intercepts of this equation.
\(\displaystyle{7}{x}+{2}{y}={56}\)

Answers (1)

2020-12-18
Calculation:
Consider the following function
\(\displaystyle{7}{x}+{2}{y}={56}\)
For x-intercept put \(\displaystyle{y}={0}\)
\(\displaystyle{7}{x}+{2}{\left({0}\right)}={56}\)
\(\displaystyle{7}{x}={56}\)
\(\displaystyle{x}={\frac{{{56}}}{{{7}}}}\)
\(\displaystyle{x}={8}\)
Hence, the x-intercept is at (8, 0)
For y-intercept put \(\displaystyle{x}={0}\)
\(\displaystyle{7}{\left({0}\right)}+{2}{y}={56}\)
\(\displaystyle{2}{y}={56}\)
\(\displaystyle{y}={\frac{{{56}}}{{{2}}}}\)
\(\displaystyle{y}={28}\)
Hence, the y-intercept is at (0.28)
0

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