Study the behaviour of \sum_{n=1}^{\infty}\frac{n+\log(n)}{(n+\cos(n))^3}

Nyah Conrad

Nyah Conrad

Answered question

2022-02-27

Study the behaviour of
n=1n+log(n)(n+cos(n))3

Answer & Explanation

vazen2bl

vazen2bl

Beginner2022-02-28Added 9 answers

For n2 we have
n+log(n)(n+cos(n))3<n+n(nn2)3=2nn38=16n2
Thus
n=1n+log(n)(n+cos(n))3<11+cos(1)+n=216n2=11+cos(1)+8π2316

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?