How do you prove that \frac{10^n-1}{10^n-2}=1+\sum_{i=0}^\infty 2^i\times10^{-n(i+1)}

Bradlee Hooper

Bradlee Hooper

Answered question

2022-02-27

How do you prove that
10n110n2=1+i=02i×10n(i+1)

Answer & Explanation

Elijah Hunt

Elijah Hunt

Beginner2022-02-28Added 5 answers

Your sum is a geometric series:
i=02i×10n(i+1)=10ni=0(210n)i
=10n×112×10n=110n2
You are done once you observe that
10n110n2=10n210n2+110n2
=1+110n2

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