Find the x-and y-intercepts of the graph of the equation algebraically. 3y+2.5x-3.4=0

Find the x-and y-intercepts of the graph of the equation algebraically.
$3y+2.5x-3.4=0$
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Leonard Stokes
Calculation:
Consider, the equation, $3y+2.5x—3.4=0$,
To compute x-intercept, put $y=0$,
$3\cdot 0+2.5x-3.4=0$
$2.5x-3.4+3.4=0+3.4$
$\frac{2.5}{2.5}x=\frac{3.4}{2.5}$
$x=1.36$
So, the x-intercept is (1.36, 0).
To compute y -intercept, put $x=0$,
$3y+2.5×0-3.4=0$
$\frac{3y}{3}=\frac{3.4}{3}$
$y=\frac{3.4}{3}$
$y=1.13$
So, the y -intercept is (0, 1.13).
Hence, the x and y-intercepts of $3y+2.5x-3.4=0$ are (1.36,0) and (0,1.13), respectively.
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Jeffrey Jordon

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