Question

Find the x-and y-intercepts of the graph of the equation algebraically. 3y+2.5x-3.4=0

Upper level algebra
ANSWERED
asked 2020-11-08
Find the x-and y-intercepts of the graph of the equation algebraically.
\(\displaystyle{3}{y}+{2.5}{x}-{3.4}={0}\)

Expert Answers (1)

2020-11-09
Calculation:
Consider, the equation, \(\displaystyle{3}{y}+{2.5}{x}—{3.4}={0}\),
To compute x-intercept, put \(\displaystyle{y}={0}\),
\(\displaystyle{3}\cdot{0}+{2.5}{x}-{3.4}={0}\)
\(\displaystyle{2.5}{x}-{3.4}+{3.4}={0}+{3.4}\)
\(\displaystyle{\frac{{{2.5}}}{{{2.5}}}}{x}={\frac{{{3.4}}}{{{2.5}}}}\)
\(\displaystyle{x}={1.36}\)
So, the x-intercept is (1.36, 0).
To compute y -intercept, put \(\displaystyle{x}={0}\),
\(\displaystyle{3}{y}+{2.5}\times{0}-{3.4}={0}\)
\(\displaystyle{\frac{{{3}{y}}}{{{3}}}}={\frac{{{3.4}}}{{{3}}}}\)
\(\displaystyle{y}={\frac{{{3.4}}}{{{3}}}}\)
\(\displaystyle{y}={1.13}\)
So, the y -intercept is (0, 1.13).
Hence, the x and y-intercepts of \(\displaystyle{3}{y}+{2.5}{x}-{3.4}={0}\) are (1.36,0) and (0,1.13), respectively.
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