 # Find the x-and y-intercepts of the graph of the equation algebraically. y=2x+3y=10 cistG 2020-12-02 Answered
Find the x-and y-intercepts of the graph of the equation algebraically.
$y=2x+3y=10$
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Calculation:
Consider, the equation $2x+3y=10$,
To compute x-intercept, put $y=0$.
$2x+3\cdot 0=10$
$2x=10$
Divide both sides of the equation,
$\frac{2x}{2}=\frac{10}{2}$
$x=5$
So, the x-intercept is $\left(5,0\right)$.
To compute y-intercept, put $x=0$,
$2\cdot 0+3y=10$
$3y=10$
Divide both sides of the equation by 3,
$\frac{3y}{3}=\frac{10}{3}$
$y=\frac{10}{3}$
So, the y -intercept is $\left(0,\frac{10}{3}\right)$.
Hence, the x and y -intercept of $2x+3y=10$ are $\left(5,0\right)$ and $\left(0,\frac{10}{3}\right)$, respectively.
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