cistG
2020-12-02
Answered

Find the x-and y-intercepts of the graph of the equation algebraically.

$y=2x+3y=10$

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Aamina Herring

Answered 2020-12-03
Author has **85** answers

Calculation:

Consider, the equation$2x+3y=10$ ,

To compute x-intercept, put$y=0$ .

$2x+3\cdot 0=10$

$2x=10$

Divide both sides of the equation,

$\frac{2x}{2}=\frac{10}{2}$

$x=5$

So, the x-intercept is$(5,0)$ .

To compute y-intercept, put$x=0$ ,

$2\cdot 0+3y=10$

$3y=10$

Divide both sides of the equation by 3,

$\frac{3y}{3}=\frac{10}{3}$

$y=\frac{10}{3}$

So, the y -intercept is$(0,\frac{10}{3})$ .

Hence, the x and y -intercept of$2x+3y=10$ are $(5,0)$ and $(0,\frac{10}{3})$ , respectively.

Consider, the equation

To compute x-intercept, put

Divide both sides of the equation,

So, the x-intercept is

To compute y-intercept, put

Divide both sides of the equation by 3,

So, the y -intercept is

Hence, the x and y -intercept of

Jeffrey Jordon

Answered 2021-11-03
Author has **2262** answers

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