 # Find the x-and y-intercepts of the graph of the equation algebraically. \frac{8x}{3}+50-2y=0 BenoguigoliB 2021-03-06 Answered
Find the x-and y-intercepts of the graph of the equation algebraically.
$\frac{8x}{3}+50-2y=0$
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Calculation:
Consider, the equation, $\frac{8x}{3}+5—2y=0$,
To compute x-intercept, put $y=0$,
$\frac{8x}{3}+5—2\cdot 0=0$
$\frac{8x}{3}+5-5=0-5$
$\frac{3}{8}\cdot \frac{8x}{3}=\frac{3}{8}\cdot \left(-5\right)$
$x=\frac{-15}{8}$
So, the x-intercept is $\left(\frac{-15}{8},0\right)$.
To compute y -intercept, put $x=0$,
$\frac{8\cdot 0}{3}+5-2y=0$
$5-2y-5=0-5$
$\frac{-2}{-2}y=\frac{-5}{2}$
$y=\frac{-5}{-2}$
So, the y-intercept is $\left(0,\frac{5}{2}\right)$.
Hence, the x and y -intercepts of $\frac{8x}{3}+5-2y=0$ are $\left(\frac{-15}{8},0\right)$ and $\left(\frac{-15}{8},0\right)$ and $\left(0,\frac{5}{2}\right)$,respectively.
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